THANK's to the "Division of Chemistry" of the "Sheffield Hallam University" .  —   A very good job! Peter Forster.
(But I by myself will consequently use the Terms:  Absorption,  Absorptivity.)
SORRY! But with some green I made it PHYSICAL and ALGEBRAIC a little bit MORE CORRECT! Peter Forster.


Do you know:    The Beer-Lambert-Bouguer-law as usually written, is only the half of the true?
                          The more correct answer: 
The:  GENERAL BEER LAMBERT LAW !
[7]
Peter Forster.
Home to: Peter Forster


NEW       Have you also seen my: "Beer-Lambert Law  FAQ's / Spectroscopy  FAQ's"?       NEW
                              (FAQ's:  Frequently Asked Questions)

Introduction

Many compounds absorb ultraviolet (UV: ˜190 nm - ˜370 nm) or visible (Vis.: ˜370 nm - ˜800 nm) light.
The diagram below shows a beam of  monochromatic [1] radiation of radiant power P0, directed at a sample solution. Absorption takes place and the beam of radiation leaving the sample has radiant power P.

The amount of radiation absorbed may be measured in a number of ways:

Transmittance:         T = P / P0
% Transmittance: %T = 100 T

Absorbance:

A = log10 (P0 / P)
A = log10 (1 / T)     = -log10 (T)
A = log10 (100 / %T)
A = 2 - log10 (%T)

The last equation, A = 2 - log10 (%T) , is worth remembering because it allows you to easily calculate absorbance from percentage transmittance data.

The relationship between absorbance and transmittance is illustrated in the following diagram:

So, if all the light passes through a solution without any absorption, then absorbance is zero, and percent transmittance is 100%. If all the light is absorbed, then percent transmittance is zero, and absorption is infinite.


The Beer-Lambert Law (Beer's Law)

Now let us look at the Beer-Lambert law and explore it's significance. This is important because people who use the law often don't understand it - even though the equation representing the law is so straightforward:

A(λ, env)= ε(λ, env)b c     [*]

Where A is absorbance (no units, since A = log10 (P0 / P) ).     Almost used Unit:    AU = Absorption Unit = 1.
  mAU = milli AU.

ε(λ, env) is the molar absorbtivity with units of L mol -1 cm-1 ;   but depends largely upon the wavelength of the measuring light.
  (used Synonyms: Molar absorptivity;
Molar absorption;
Molar extinctivity;
Molar extinction

Molar absorptivity coefficient;
Molar absorption coefficient;
Molar extinctivity coefficient;
Molar extinction coefficient;
(Molar) Specific absorptivity;   . . . . )
        "Molar" means[2,3], all times the same number of 'molecules' inside the measuring beam (if b = const.)
b is the path length of the sample - that is, the path length of the cuvette in which the sample is contained. We will express this measurement in centimetres.
c is the concentration of the compound in solution, expressed in mol L -1

(Remember:   MolaRity = mol / L Solution;   MolaLity = mol / kg Solvent !)

The reason why we prefer to express the law with this equation is because absorbance is directly proportional to the other parameters, as long as the law is obeyed. We are not going to deal with deviations from the law. (Why ??)

Let's have a look at a few questions...

Question : Why do we prefer to express the Beer-Lambert law using absorbance as a measure of the absorption rather than %T ?

Answer : To begin, let's think about the equations...

A(λ, env)= ε(λ, env) b c     [*]

%T(λ, env) = 100 P(λ, env)/P0(λ, env) = e (λ, env)bc

Now, suppose we have a solution of copper sulphate (which appears blue because it has an absorption maximum at 600 nm). We look at the way in which the intensity of the light (radiant power) changes as it passes through the solution in a 1 cm cuvette. We will look at the reduction every 0.2 cm as shown in the diagram below. The Law says that the fraction of the light absorbed by each layer of solution is the same. For our illustration, we will suppose that this fraction is 0.5 for each 0.2 cm "layer" and calculate the following data:

Total Path length [cm]
0
0.2
0.4
0.6
0.8
1.0
%T
100
50
25
12.5
6.25
3.125
Absorbance [AUs]
0
0.3
0.6
0.9
1.2
1.5

A(λ, env) = ε(λ, env)bc tells us that absorbance depends on the total quantity of the absorbing compound in the light path through the cuvette. If we plot absorbance against concentration, we get a straight line passing through the origin (0,0).

Note that the Law is not obeyed at high concentrations.
  ( THAT's NOT TRUE !!!  —  Do YOU know why? ) 
If you don't have any idea, — then you have NOT UNDERSTOOD
Beer-Lambert-Bouguer!          Hint:   Try to think "GENERAL" !! [4,5,6]


This deviation from the Law is not dealt with here.

The linear relationship between concentration and absorbance is both simple and straightforward, which is why we prefer to express the Beer-Lambert law (Please - Beer's Law, not Ber's Law) using absorbance as a measure of the absorption rather than %T.
(Be told: This simple and straightforward relationship between concentration and absorbance is only for the "Special Beer-Lambert Law" and over a restricted concentration range true!  More correct ... ... .[7][8])

Question : What is the significance of the molar absorbtivity, ε(λ, env) ?

Answer : To begin we will rearrange the equation A(λ, env) = ε(λ, env)bc [*]:

ε(λ, env) = A(λ, env) / bc     [*]

In words, this relationship can be stated as:
  "ε(λ, env) is a measure of the amount of light absorbed per unit concentration at the measuring wavelength (λ, env)!".

Molar absorbtivity is a constant for a particular substance at the measuring wavelength (λ, env), so if the concentration of the solution is halved so is the absorbance, which is exactly what you would expect.

Let us take a compound with a very high value of molar absorbtivity, say 100,000 L mol -1 cm-1, which is in a solution in a 1 cm pathlength cuvette and gives an absorbance of 1 AU.

ε(λ, env) = 1(λ, env) / 1 x c

Therefore, c = 1 / 100,000 = 1 x 10-5 mol L-1

Now let us take a compound with a very low value of ε(λ, env), say 20 L mol-1 cm-1 which is in solution in a 1 cm pathlength cuvette and gives an absorbance of 1.

ε(λ, env) = 1(λ, env) / 1 ´ c

Therefore, c = 1 / 20 = 0.05 mol L-1

The answer is now obvious - a compound with a high molar absorbtivity is very effective at absorbing light (of the appropriate wavelength), and hence low concentrations of a compound with a high molar absorbtivity can be easily detected.

Question : What is the molar absorbtivity of Cu2+ ions in an aqueous solution of CuSO4 ? It is either 20 or 100,000 L mol-1 cm-1

Answer : I am guessing that you think the higher value is correct, because copper sulphate solutions you have seen are usually a beautiful bright blue colour. However, the actual molar absorbtivity value is 20 L mol-1 cm-1 ! The bright blue colour is seen because the concentration of the solution is very high.

b-carotene is an organic compound found in vegatables and is responsible for the colour of carrots. It is found at exceedingly low concentrations. You may not be surprised to learn that the molar absorbtivity of b-carotene is 100,000 L mol-1 cm-1 !

The "CRIB": [german: "Die Eselsleiter"[E] ] (for all, who likes so very much molar absorbtivity; molar absorptivity):

"Draw exactly" the picture the equation is telling you, and think of ε(λ, env.) as of a concentration for your substance, in the manner of:   Who many Litres of solvent you need for diluting ONE Mole of your compound to measure ONE Absorption in the ONE cm Cuvette at your measuring Wavelength.
"That means", if you need a lot of Litres, that you have a strong absorber, and if you need only a few Litres, that you have a weak absorber in your cuvette. — That's it.  Now it's absolute easy to calculate all you like.

Review your learning

You should now have a good understanding of the Beer-Lambert Law; the different ways in which we can report absorption, and how they relate to each other. You should also understand the importance of molar absorbtivity, and how this affects the limit of detection of a particular compound.


And now, what's about:   The:  GENERAL BEER LAMBERT LAW ? [7] Peter Forster.


References References:
 
[*] "Do you know, that this equation is still not correct and never correct enough?:"
 
The big mistakes are located in ε(λ, env)
Mother natur learned us, that we have to rewrite it at least as: 
Molar absorptivity:
  ε( λ, sw, [pH], solv, temp, μΘ, B,   etc.)
λ       : wavelength
sw     : Slit width in use.
pH    : equiv. Proton concentration
solv   : Solvent or Mixture or Matrix.
temp  : Temperature.
μΘ    : phys. & chem. Reaction State.
B      : Magnetic Field.
Now you must already be able to estimate by yourself of how much practical value all the published "molar" and not so "molar" absorptivity/extinction coefficient and their precision are!
-  Don't ask me, why nobody takes ever care of!  
-  Why also, is everybody so keen to tell you about:
TROUBLES & EXCEPTIONS & LIMITS & DEVIATIONS & 'NOT OBEYED' & 'PROBLEMS' of:
The Beer-Lambert-Bouguer-law?
-  But now you know, why I never used a ε-Value from the Literatur.
-  I'm sure, NOW you can tell me the value for all published "molar" absorptivity coefficient for your copper sulfate!
There is also a lot of Information on my:" Spectroscopy FAQ's / Beer-Lambert-Bouguer Law FAQ's" Page for you.
(FAQ's:  Frequently Asked Questions)

There you will also be able to discover, why I wrote [pH] instead of pH.
Shortly I will correct all my equations and terms.
Till then replace each (λ) by "(λ, env.)" , what stands for the environment of the measured species, too.
[1] "Spectroscopy: Monochromatic:
      Do you know, Who felt himself competent enough to 'introduce' the term "monochromatic"
      to The Beer-Lambert-Bouguer-law (BLBL) in such a .... kind?
      It's such an easy game to play, to show you the evidence of THE ABSOLUT CONTRARY !!:
"monochromatic" .IS NEVER a Requirement for The BLBL !      
      www.p-forster.com/english/themes/spectroscopy/Spectroscopy_FAQ.htm#FAQ_US01
[2] "Molar:   —  is the Measure of Concentrations in the Unit: Mole per Litre”
      Note: Mole is a number of 'molecules' ("species") expressed as a weight!
      Mole: http://en.wikipedia.org/wiki/Mole (Unit)
[3] "Molar:”   —  is very frequently used on universities, colleges, and schools!
      Note: Molar is very rarely used in the practical field (quality control) and production!
      Molar makes only sense, if you are interested in comparing transition probabilities,
      oscillator strength? (force?), and other such parameters of different species.
      Molar:  1.0 molar  =  6.0221415 × 1023 'molecules' ('species') in 1.0 Litre SOLUTION!
      http://en.wikipedia.org/wiki/Concentration#Molarity
[4] "Spectroscopy: Lesson 2:
      6.  That's real linearity and how you have to test it !"    [Paragraph 5.), case a.)]
      www.p-forster.com/english/themes/spectroscopy
[5] "Spectroscopy: Lesson 1:
      1.  .... (We were never able, to find a real case, when a solution was not following strictly the law of Beer - Lambert! ! ....)
      www.p-forster.com/english/themes/spectroscopy
[6] "Linearity:   —  maybe a little more?”
      www.p-forster.com/english/themes/Spectroscopy/Linearity.htm
[7] The:  GENERAL BEER LAMBERT LAW !!!:
      That's the TRUE as mother nature, Mr. A. Beer, Mr. J. H. Lambert, and Mr. P. Bouguer are telling you.
      Read: www.p-forster.com/english/themes/Spectroscopy/Spectroscopy.htm
[8] "Why has direct proportionality from Concentration to Absorbance such Lacks?
      Or have you other such "Frequently Asked Questions" (FAQ's):
      UV/Vis- NNIR- NIR- Spectroscopy FAQ's / Beer-Lambert-Bouguer Law FAQ's
[E] "Eselsleitergerman:”   —   Esel -> donkey     Leiter -> leader
      Eselsleiter means a 'mnemonic trick' like a leader even a donkey may be able to climb. 



Beer's Law - Quiz
Corrected Beer's Law
UV-Vis. Absorption spectroscopy


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